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Perplex
Perplex
Dashboard
Topics
Exponents & LogarithmsApproximations & ErrorSequences & SeriesCounting & BinomialsProof and ReasoningComplex NumbersAlgebra Skills
Cartesian plane & linesQuadraticsFunction TheoryTransformations & asymptotesPolynomials
2D & 3D GeometryTrig equations & identitiesVectors
ProbabilityDescriptive StatisticsBivariate StatisticsDistributions & Random Variables
DifferentiationIntegrationDifferential EquationsMaclaurin
Review VideosFormula BookletMy Progress
BlogLanding Page
Sign UpLogin
Perplex
/
Vectors
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Scalar product
Vector Product
Scalar product
Vectors

Scalar product

0 of 0 exercises completed

The scalar (aka dot) product, and its connection to angles between vectors.

Want a deeper conceptual understanding? Try our interactive lesson!

Scalar product
AHL 3.13

The scalar product, also called the dot product, takes two vectors and produces a scalar (a number). For two vectors ​v=⎝⎛​v1​v2​v3​​⎠⎞​​ and ​w=⎝⎛​w1​w2​w3​​⎠⎞​, the scalar product is calculated as:

​
v⋅w=v1​w1​+v2​w2​+v3​w3​📖
​

This operation combines corresponding components of each vector, resulting in a single numerical value.

The scalar product measures the extent to which two vectors point in the same direction. The bigger the vectors and the more they point in the same direction, the bigger the scalar product, since only the "parallel parts" contribute to the dot product. It's is a scalar quantity measuring the amount of similarity.

Angle between vectors
AHL 3.13

The scalar product also has a geometric interpretation involving the angle ​θ​ between two vectors:

​
v⋅w=∣v∣∣w∣cosθ📖
​

Equivalently, isolating ​cosθ:

​
cosθ=∣v∣∣w∣v1​w1​+v2​w2​+v3​w3​​📖
​


The angle ​θ​ is measured between the heads of ​v​ and ​w:

Acute vs Obtuse Angles
AHL 3.13

If the scalar product of two vectors is negative, then

​
cosθ=∣u∣⋅∣v∣u⋅v​<0
​

and thus ​θ​ must be an obtuse angle: ​90°<θ≤180°.


But since vectors always form an acute AND an obtuse angle, we can find the acute angle by subtracting

​
180°−θ
​

whenever ​θ>90°.


Perpendicular vectors
AHL 3.13

Since ​v⋅w=∣v∣∣w∣cosθ, if two vectors are perpendicular then ​cos90°=0⇒​ their scalar product is ​0.

Properties of the scalar product
AHL 3.13

For any vectors ​u,  ​v, and ​w, and scalar ​k:


​
u⋅v=v⋅u🚫
​


​
u⋅(v+w)=u⋅v+u⋅w🚫
​


​
(ku)⋅v=k(u⋅v)=u⋅(kv)🚫
​


​
u⋅u=∣u∣2🚫
​


Nice work completing Scalar product, here's a quick recap of what we covered:

Skills covered

Mixed Practice

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/
Vectors
/
Scalar product
Vector Product
Scalar product
Vectors

Scalar product

0 of 0 exercises completed

The scalar (aka dot) product, and its connection to angles between vectors.

Want a deeper conceptual understanding? Try our interactive lesson!

Scalar product
AHL 3.13

The scalar product, also called the dot product, takes two vectors and produces a scalar (a number). For two vectors ​v=⎝⎛​v1​v2​v3​​⎠⎞​​ and ​w=⎝⎛​w1​w2​w3​​⎠⎞​, the scalar product is calculated as:

​
v⋅w=v1​w1​+v2​w2​+v3​w3​📖
​

This operation combines corresponding components of each vector, resulting in a single numerical value.

The scalar product measures the extent to which two vectors point in the same direction. The bigger the vectors and the more they point in the same direction, the bigger the scalar product, since only the "parallel parts" contribute to the dot product. It's is a scalar quantity measuring the amount of similarity.

Angle between vectors
AHL 3.13

The scalar product also has a geometric interpretation involving the angle ​θ​ between two vectors:

​
v⋅w=∣v∣∣w∣cosθ📖
​

Equivalently, isolating ​cosθ:

​
cosθ=∣v∣∣w∣v1​w1​+v2​w2​+v3​w3​​📖
​


The angle ​θ​ is measured between the heads of ​v​ and ​w:

Acute vs Obtuse Angles
AHL 3.13

If the scalar product of two vectors is negative, then

​
cosθ=∣u∣⋅∣v∣u⋅v​<0
​

and thus ​θ​ must be an obtuse angle: ​90°<θ≤180°.


But since vectors always form an acute AND an obtuse angle, we can find the acute angle by subtracting

​
180°−θ
​

whenever ​θ>90°.


Perpendicular vectors
AHL 3.13

Since ​v⋅w=∣v∣∣w∣cosθ, if two vectors are perpendicular then ​cos90°=0⇒​ their scalar product is ​0.

Properties of the scalar product
AHL 3.13

For any vectors ​u,  ​v, and ​w, and scalar ​k:


​
u⋅v=v⋅u🚫
​


​
u⋅(v+w)=u⋅v+u⋅w🚫
​


​
(ku)⋅v=k(u⋅v)=u⋅(kv)🚫
​


​
u⋅u=∣u∣2🚫
​


Nice work completing Scalar product, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!

Generating starter questions...