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Exponents & Logarithms

Exponents & Logarithms

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Radicals and Roots

Discussion

So far, we have only seen integer exponents, but fractional exponents exist too. Using your knowledge of exponential laws, determine the value of 6431​.

We want to find 641/3. Recall the law of exponents

(an)m=anm

and set

x=641/3.

Then

x3=(641/3)3=64(1/3)⋅3=641=64

so x is a number whose cube is 64. Since 43=64, we conclude

641/3=4.


Basically, we have found that 6431​ is the number whose cube is 64.


Using the same thinking, we can see that 221​ is the number whose square is 2, but this is exactly the definition of a square root!

221​=√2


You have probably seen a square root with radical (√) notation before but there are other kinds of roots! We typically write them in radical form as:

n√a.


The radical notation for a square root is a shorthand since the square root is the most common root, but we can write square roots with the more general notation too:

221​=√2=2√2.


Returning to our original example, now we can say:

6431​=3√64.


We call this the cube root of 64, or the number whose cube is 64.

nth Roots

For any number a and whole number n,

n√a

is called the nth root of a.


The nth root of a is the number that gives you a when raised to the nth power:

(n√a)n.

Note that this root is positive when n is even.

Checkpoint

5√6 raised to what power equals 6?

Select the correct option

Discussion

Does −64 have a real square root? How about a cube root?

For a real square root of −64, we would need a real x satisfying

x2=−64.

Since x2=x⋅x is either a product of two positive numbers or a product of two negative numbers, x2≥0 for every real x, so there is no real solution.


For a cube root, we solve

x3=−64

and observe that

(−4)3=−64,

so the cube root of −64 is −4.


Roots of negative numbers

If a is negative, n√a is negative for all odd n.


For even n, no real n√a exists.

Checkpoint

Evaluate 3√−27​.

Select the correct option

Recall that we introduced the roots 3√64 and √2 as fractional exponents. We can do this with any nth root!

Converting nth roots to fractional exponents

Roots can always be written as fractional exponents and vice versa:


n√a=an1​.

Checkpoint

Write 8√26 as an exponent.

Select the correct option

Discussion

Now, we can understand fractional exponents of the form an1​ through our knowledge of nth roots! However, can we interpret other rational exponents, like 52​?

Utilizing your knowledge of nth roots and exponential laws, determine the value of 3252​.

First, note that

52​=(51​)⋅2

and use (an)m=anm:

322/5=32(51​⋅2)=(321/5)2


Next, 321/5 denotes the 5th root of 32. Since 25=32,

321/5=2


Finally, substitute back:

322/5=22=4.


Rational exponents

Utilizing nth roots and exponential laws we can rewrite any rational exponent:


anm​=(an1​)m=n√am=(n√a​)m


Exercise

Write 7√x61​ in the form xa/b.

Select the correct option

Exercise

Evaluate 12532​.

Select the correct option

Now, that we understand what nth roots are, we can learn about their algebraic properties.


First, since roots are a type of exponent, all of our exponent rules carry over to roots. For example, we learned that

(ab)n=anbn,

so we can see that

n√ab=(ab)n1​=an1​bn1​=n√a⋅n√b.

Understanding that

n√ab=n√a⋅n√b,

we can learn how to put radicals into simplest form.

Simplest form radicals

A radical is in simplest form if the integer under the radical sign is as small as possible.


For example, the simplest form of √48 is 4√3. We can simplify by splitting the radical into a reducible and irreducible part:


√48=√16⋅√3=4√3.

Checkpoint

Simplify 4√96.

Select the correct option

Exercise

Simplify as much as possible (3√272√3⋅√12​)3.

Select the correct option

We can also simplify fractions containing radicals:

Simplest form fractions with radicals (multiplying by roots)

A fraction in simplest form does not have a radical in the denominator.


For a fraction of the form √ba​ where a∈Z,b∈N, we find the simplest form by mutliplying the numerator and denominator by √b:

√ba​=ba√b​.

When we remove a radical from a denominator, we call it rationalizing the denominator.

Checkpoint

Simplify √21​.

Select the correct option

Discussion

However, not every fraction with a radical is of the form √ba​.


Evaluate 1+√31​⋅√3√3​. Explain whether your result is a fraction in simplest form.

We first multiply top and bottom by √3:

1+√31​⋅√3√3​=√3(1+√3)√3​=3+√3√3​


Since the denominator 3+√3 still contains a radical, 3+√3√3​ is not in simplest form.

We see that our old strategy of multiplying by a radical does not work if the denominator has another term!


The core issue we run into is that there is no nonzero number we can multiply both 1 and √3 so that both products are rational. Instead, we need to multiply the numerator and denominator of a fraction like

1+√31​

by a quantity with multiple terms.

Discussion

Using the fact that (a+b)(a−b)=a2−b2, can you find a nonzero quantity x such that (1+√3)x contains no radicals?

We want (1+√3)x to be free of radicals. Note that for any a,b,

(a+b)(a−b)=a2−b2

is rational when a2 and b2 are rational. Here a=1 and b=√3 give a2=1, b2=3. Thus

(1+√3)(1−√3)=12−(√3)2=1−3=−2.

Since 1−√3=0, set

x=1−√3.

Then

(1+√3)x=(1+√3)(1−√3)=1−3=−2

which contains no radicals.


Now, we know how to simplify 1+√31​:

1+√31​=1+√31​⋅1−√31−√3​=12−(√3)21−√3​=1−31−√3​=−21−√3​.

We multiplied the numerator and denominator by the conjugate of 1+√3.

Rationalizing Denominators with Conjugates

To simplify a fraction of the form b+√ca​, multiply the fraction by b−√cb−√c​.


b−√c is called the conjugate of b+√c.

Exercise

Rationalize the denominator in the fraction 3−√22​ and simplify.

Select the correct option

Exercise

Simplify 16−1(423​⋅2−7⋅831​)2​.

Select the correct option

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