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Graphing absolute value functions, squared functions, piecewise functions, graphing 1/f(x)
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Practice exam-style further transformations problems
To obtain the graph of βf(β£xβ£), you can think of it as:
For βxβ₯0: ββ£xβ£=x, so βf(β£xβ£)=f(x).
For βx<0: ββ£xβ£=βx, so βf(β£xβ£)=f(βx).
Practically, you take the portion of βy=f(x)β for βxβ₯0β and reflect it across the βyβ-axis to fill in the βx<0β side. The right side of the original graph becomes the entire graph of βf(β£xβ£).
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To obtain the graph of ββ£f(x)β£, take the graph of βf(x)β and:
Leave all points where βf(x)β₯0β as they are, since ββ£f(x)β£=f(x)β in that region.
Reflect any parts of the graph where βf(x)<0β above the βxβ-axis, because ββ£f(x)β£=βf(x)β whenever βf(x)β is negative.
Effectively, every negative βyβ-value becomes positive, mirroring the portion of the curve below the βxβ-axis to above it.
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Notice the "sharp corners" where the function touches the βxβ-axis.
To sketch β[f(x)]2β from βf(x):
Square all βyβ-values: for each βx, the new βyβ-value is β(f(x))2.
Because βy2β₯0, the entire graph of β[f(x)]2β is on or above the βxβ-axis.
Points where βf(x)=0β remain on the βxβ-axis.
Any minima below the βxβ-axis become maxima above the βxβ-axis.
Any maxima below the βxβ-axis become minima above the βxβ-axis.
If ββ£f(x)β£<1, squaring makes it closer to 0; if ββ£f(x)β£>1, squaring makes it larger.
Negative parts of βf(x)β become positive when squared, so everything below the βxβ-axis is reflected above it, with the magnitude of βyβ-values adjusted according to the square.
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Notice the "rounded corners" where the function touches the βxβ-axis, as opposed to the sharp corners for ββ£f(x)β£.
To sketch βf(x)1ββ from βf(x):
At every βxβ-value, take the reciprocal of the original βyβ-value: βyβy1β.β
Points where βf(x)=0β become vertical asymptotes, since β01ββ is undefined.
If ββ£f(x)β£β is large, then βf(x)1ββ is small (close to the βxβ-axis). Thus, vertical asymptotes of βf(x)β become horizontal asymptotes at βy=0. Conversely, if ββ£f(x)β£β is small, then βf(x)1ββ is large.
Local maxima and minima "flip":
a maximum at β(a,b)β on βf(x)β becomes a minimum at β(a,b1β)β on βf(x)1β;
a minimum at β(c,d)β becomes a maximum at β(c,d1β). This happens because reciprocal values invert magnitudes.