Binomial Theorem

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Using nCr to expand binomials like (1+2x)7.

The expansion of (a+b)ⁿ

SL AA 1.9

The binomial theorem allows us expand expressions of the form (a+b)n:

(a+b)n=an+nC1an−1b1+nC2an−2b2+⋯📖

or in summation form:

(a+b)n=r=0∑n(nr)an−rbr🚫

Nice work completing Binomial Theorem, here's a quick recap of what we covered:

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Counting

Counting & Binomials

Binomial Theorem

0 of 0 exercises completed

Using nCr to expand binomials like (1+2x)7.

The expansion of (a+b)ⁿ

SL AA 1.9

The binomial theorem allows us expand expressions of the form (a+b)n:

(a+b)n=an+nC1an−1b1+nC2an−2b2+⋯📖

or in summation form:

(a+b)n=r=0∑n(nr)an−rbr🚫

Nice work completing Binomial Theorem, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!

Generating starter questions...

Counting

Counting & Binomials

Binomial Theorem

0 of 0 exercises completed

Using nCr to expand binomials like (1+2x)7.

The expansion of (a+b)ⁿ

SL AA 1.9

The binomial theorem allows us expand expressions of the form (a+b)n:

(a+b)n=an+nC1an−1b1+nC2an−2b2+⋯📖

or in summation form:

(a+b)n=r=0∑n(nr)an−rbr🚫

Nice work completing Binomial Theorem, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!

Generating starter questions...

Counting

Counting & Binomials

Binomial Theorem

0 of 0 exercises completed

Using nCr to expand binomials like (1+2x)7.

The expansion of (a+b)ⁿ

SL AA 1.9

The binomial theorem allows us expand expressions of the form (a+b)n:

(a+b)n=an+nC1an−1b1+nC2an−2b2+⋯📖

or in summation form:

(a+b)n=r=0∑n(nr)an−rbr🚫

Nice work completing Binomial Theorem, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!

Generating starter questions...

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