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Perplex
Perplex
  • Dashboard
Topics
Exponents & LogarithmsRounding & ErrorSequences & SeriesFinancial MathematicsMatricesComplex Numbers
Cartesian plane & linesFunction TheoryModellingTransformations & asymptotes
2D & 3D GeometryVoronoi DiagramsTrig equations & identitiesVectorsGraph Theory
ProbabilityDescriptive StatisticsBivariate StatisticsDistributions & Random VariablesInference & Hypotheses
DifferentiationIntegrationDifferential Equations
Paper 3
Plus
Calculator Skills
Review VideosFormula BookletAll Study Sets
BlogLanding Page
Sign UpLogin
Perplex
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Complex Numbers
/
Powers of Complex Numbers
Mixed Practice
Powers of Complex Numbers
Complex Numbers

Powers of Complex Numbers

0 of 0 exercises completed

Using De Moivre's Theorem to find powers of complex numbers in polar form, ​z=reiθ, so that ​zn=rneinθ=rncis(nθ), and applying the argument rule ​arg(zw)=arg(z)+arg(w).

Want a deeper conceptual understanding? Try our interactive lesson! (Plus Only)

Powers of complex numbers
AHL AI 1.13

Now that we know how to represent complex numbers in the form ​reiθ, we can understand De Moivre's Theorem, which gives us a shortcut to finding powers of complex numbers:

​
z=reiθ⇒zn=(reiθ)n=rneinθ
​


And since ​reiθ=rcisθ:

​
[r(cosθ+isinθ)]n=(rcisθ)n=rneinθ=rncis(nθ)📖
​

Nice work completing Powers of Complex Numbers, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!
/
Complex Numbers
/
Powers of Complex Numbers
Mixed Practice
Powers of Complex Numbers
Complex Numbers

Powers of Complex Numbers

0 of 0 exercises completed

Using De Moivre's Theorem to find powers of complex numbers in polar form, ​z=reiθ, so that ​zn=rneinθ=rncis(nθ), and applying the argument rule ​arg(zw)=arg(z)+arg(w).

Want a deeper conceptual understanding? Try our interactive lesson! (Plus Only)

Powers of complex numbers
AHL AI 1.13

Now that we know how to represent complex numbers in the form ​reiθ, we can understand De Moivre's Theorem, which gives us a shortcut to finding powers of complex numbers:

​
z=reiθ⇒zn=(reiθ)n=rneinθ
​


And since ​reiθ=rcisθ:

​
[r(cosθ+isinθ)]n=(rcisθ)n=rneinθ=rncis(nθ)📖
​

Nice work completing Powers of Complex Numbers, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!

Generating starter questions...

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Generating starter questions...

1 free