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  • Perplex
    IB Math AASL
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    Differentiation
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    Skills

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    Skill Checklist

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    Skill Checklist

    Track your progress across all skills in your objective. Mark your confidence level and identify areas to focus on.

    25 Skills Available

    Track your progress:

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    Confident

    📖 = included in formula booklet • 🚫 = not in formula booklet

    Track your progress:

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    📖 = included in formula booklet • 🚫 = not in formula booklet

    Limits and Derivatives

    9 skills
    Basic concept of a limit
    SL 5.1

    The limit x→alim​f(x) is the value f(x) approaches as x approaches a.

    Slope as a Limit
    SL 5.1

    The IB may test your understanding of the gradient of the curve as the limit of

    m=x2​−x1​y2​−y1​​

    as (x2​−x1​) goes to zero.


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    Limit from a graph
    SL 5.1

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    x→1lim​f(x)=2
    x→∞lim​f(x)=23​
    x→−∞lim​f(x)=23​
    Limit from a table
    SL 5.1

    Given a table of values:

    xf(x)​0.91.62​0.991.9121​0.9991.9972201​……​


    x→1lim​f(x)=2
    Gradient
    SL 5.1

    For a curve y=f(x), f′(x) is the gradient or slope.

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    Graphing a derivative with a GDC
    SL 5.1

    You can graph f′(x) using the following steps:

    • Press the Y= key.

    • In one of the available function lines (e.g. Y_1), enter the expression for f(x).

    • In another available line (e.g. Y_2), input the derivative function usingMATH then 8:nDeriv( in the following format:

      dXd​(Y1​(x))∣X=X​


    • To enter Y1​, press VARS then scroll to Y-VARS and select FUNCTION then Y1​.

    • Press GRAPH to display both the original graph f and the derivative f′.

    • The graph of f′ may take a little bit longer depending on the original function.

    After graphing f′, you may use all the other graphing functions on the calculator (intersect, zero, and value).

    Rate of Change
    SL 5.1

    dxdy​ is the rate of change of y with respect to x. That is, dxdy​ tells us how much y changes in response to a change in x.


    If y=f(x), then dxdy​=f′(x).

    Derivative of xⁿ where n is an integer
    SL 5.3
    f(x)=xn, n∈Z⇒f′(x)=nxn−1📖
    Derivatives of sums and scalar multiples
    SL 5.3
    dxd​(af(x))=af′(x)🚫
    dxd​(f(x)+g(x))=f′(x)+g′(x)🚫
    dxd​(af(x)+bg(x))=af′(x)+bg′(x)🚫

    Differentiation rules

    8 skills
    Derivative of xⁿ where n is an integer
    SL 5.3
    f(x)=xn, n∈Z⇒f′(x)=nxn−1📖
    Derivatives of sums and scalar multiples
    SL 5.3
    dxd​(af(x))=af′(x)🚫
    dxd​(f(x)+g(x))=f′(x)+g′(x)🚫
    dxd​(af(x)+bg(x))=af′(x)+bg′(x)🚫
    Derivative of xⁿ where n is rational
    SL 5.6
    f(x)=xn, n∈Q⇒f′(x)=nxn−1📖
    Chain rule
    SL 5.6
    (g(f(x)))′=g′(f(x))⋅f′(x)🚫
    y=g(u) where u=f(x)
    dxdy​=dudg​⋅dxdu​📖
    Derivative of e^x
    SL 5.6
    f(x)=ex⇒f′(x)=ex📖
    Derivative of ln
    SL 5.6
    f(x)=lnx⇒f′(x)=x1​📖
    Product and Quotient rule
    SL 5.6

    The product and quotient rules are given by

    (uv)′=u′v+v′u📖
    (vu​)′=v2u′v−v′u​📖
    Derivatives of sin and cos
    SL 5.6
    f(x)=sinx⇒f′(x)=cosx📖
    g(x)=cosx⇒g′(x)=−sinx📖

    Tangents and normals

    2 skills
    Tangent to f(x)
    SL 5.4

    L:mx+c is tangent to f(x) at x=a means

    same ysame y′​{f(a)=ma+cf′(a)=m​🚫

    Using point slope form the equation of the tangent is:

    y−f(a) ⇒y​=m⋅(x−a)🚫 =mx−ma+f(a)🚫​


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    Normal to f(x)
    SL 5.4

    The normal to f(x) at x=a is the line that passes through (a,f(a)) and is perpendicular to the tangent:

    mn​⋅mt​=−1⇔mn​  ​=−mt​1​🚫 =−f′(a)1​🚫​

    Using point slope form the equation of the tangent is:

    y−f(a) ⇒y​=mn​⋅(x−a)🚫 =mn​x−mn​a+f(a)🚫​

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    Applications of the First Derivative

    3 skills
    Stationary points & Increasing/Decreasing Regions
    SL 5.2
    f′(x)⎩⎪⎨⎪⎧​<0⇔f decreasing=0⇔f stationary>0⇔f increasing​🚫
    Maxima & Minima
    SL 5.7

    Stationary points are often local extrema.


    If f′(a)=0, f is decreasing to the left of a (f′(x)<0), and f is increasing to the right of a (f′(x)>0), then (a,f(a)) is a local minimum.


    If f′(a)=0, f is increasing to the left of a (f′(x)<0), and f is decreasing to the right of a (f′(x)>0), then (a,f(a)) is a local maximum.

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    Optimisation
    SL 5.8

    Optimisation problems require you to find a minimum or maximum value by producing a function f(x), taking its derivative, solving f′(x)=0, and confirming which stationary point(s) are minima or maxima.

    Second Derivatives and Applications

    5 skills
    Second Derivative
    SL 5.7

    The derivative of the derivative of a function is its second derivative:

    f′′(x)=(f′(x))′🚫
    dx2d2y​=dxd​(dxdy​)=y′′🚫
    Concavity
    SL 5.7

    We determine concavity by the sign of f′′:

    f′′{>0⇔f concave up<0⇔f concave down​🚫

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    Classifying stationary points using the second derivative
    SL 5.7

    At a stationary point (f′(a)=0),

    • If f′′(a)>0, then f has a local minimum at x=a.

    • If f′′(a)<0, then f has a local maximum at x=a.

    Using the second derivative to classify a stationary point is often called the second derivative test.

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    Inflexion Points
    SL 5.7

    Inflexion points occur when f′′(x)=0 and f′′(x) changes sign. 🚫

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    Graphs of f, f' and f''
    SL 5.7

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    • When f′ crosses the x-axis f has a maximum (f′′<0) or minimum (f′′>0)

    • When f′′ crosses the x-axis, f has an inflexion point.