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  • Perplex
    IB Math AASL
    /
    Cartesian plane & lines
    /

    Line Intersections & Systems of Equations

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    Exercises

    Key Skills

    Line Intersections & Systems of Equations

    Line Intersections & Systems of Equations

    Parallel and perpendicular lines, intersection of ​2​ straight lines, solving a two-variable system of equations

    Want a deeper conceptual understanding? Try our interactive lesson!

    Exercises

    No exercises available for this concept.

    Practice exam-style line intersections & systems of equations problems

    Key Skills

    Parallel lines
    SL Core 2.1

    Two lines are parallel when they have the same gradient ​m​ and they do not intersect:

    ​
    m1​x+c1​∥m2​x+c2​⇔m1​=m2​ and c1​=c2​
    ​

    In this case, the system of equations formed by the two lines has no solutions.


    If the lines have the same gradient and they intersect, then they must be the same line.

    Intersections of straight lines
    SL Core 2.1

    Suppose we have the straight lines ​y=3x−2​ and ​y=2−3x. Where do the lines intersect?


    Lines intersect when they have a point in common. That is, for some ​x:

    ​
    3x−2=2−3x
    ​

    Rearranging gives

    ​
    6x=4⇒x=32​
    ​


    If two lines do not intersect, then they must be parallel, since the definition of parallel is two straight lines that never meet.


    If two lines are the same (possibly in different forms), then their intersection will all real numbers.

    Perpendicular Lines
    SL Core 2.1

    Two lines are perpendicular if they form a right angle with respect to each other. In this case, the rise of one line becomes the run of the other, with a sign change:

    ​
    m1​×m2​=−1
    ​

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    Systems of equations with 2 unknowns
    SL Core 2.1

    Suppose we have straight lines with equation ​3y+2x−2=0​ and ​2y−3x+1=0. Where do the lines intersect?


    We have the system of equations

    ​
    {3y+2x−2=03y−3x+1=0​
    ​


    There are two ways of solving this.

    By substitution

    Rearranging

    ​
    3y+2x−2=0⇒y=−32​x+32​
    ​


    Substituting this into ​3y−3x+1=0:

    ​
    (−2x+2)−3x+1=0
    ​
    ​
    −5x=−3
    ​

    So ​x=53​, which implies ​y=−32​⋅53​+32​=154​. So the intersection is ​(53​,154​).


    By elimination

    We can eliminate ​y​ from the equations by subtracting the second from the first:

    ​
    (3y+2x−2)−(2y−3x+1)2x−2+3x−15x​=0=0=3​
    ​

    So ​x=53​⇒y=154​​ and the intersection is again ​(53​,154​).


    We can use either of these methods to systems of equations with 2 equations and 2 unknowns.