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Perplex
Perplex
  • Dashboard
Topics
Exponents & LogarithmsRounding & ErrorSequences & SeriesCounting & BinomialsProof and ReasoningComplex NumbersAlgebra Skills
Cartesian plane & linesQuadraticsFunction TheoryTransformations & asymptotesPolynomials
2D & 3D GeometryTrig equations & identitiesVectors
ProbabilityDescriptive StatisticsBivariate StatisticsDistributions & Random Variables
DifferentiationIntegrationDifferential EquationsMaclaurin
Paper 3
Plus
Calculator Skills
Review VideosFormula BookletAll Study Sets
BlogLanding Page
Sign UpLogin
Perplex
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Integration
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Definite Integrals, Areas, and Basic Anti-Derivatives
Anti-Derivative Rules
Definite Integrals, Areas, and Basic Anti-Derivatives
Integration

Definite Integrals, Areas, and Basic Anti-Derivatives

0 of 0 exercises completed

Evaluating definite integrals ​∫ab​f(x)dx=F(b)−F(a), using anti-derivatives ​∫f(x)dx=F(x)+C​ and the power rule ​∫xndx=n+1xn+1​+C​ for ​n=−1, with linearity, splitting or combining intervals, boundary conditions, and finding areas under a curve, between a curve and the ​x​-axis, or between two curves using ​∣f(x)∣​ and ​∣f(x)−g(x)∣.

Want a deeper conceptual understanding? Try our interactive lesson!

Area under a curve
SL 5.5

The area between a curve ​f(x)>0​ and the ​x​-axis is given by

​
A=∫ab​f(x)dx📖
​
Integration as reverse differentiation
SL 5.5

Integration, or anti-differentiation, is essentially the opposite of differentiation. We use the integral symbol​∫​ and write:

​
∫f(x)dx=a function with a derivative off(x)
​

By convention we denote this function ​F:

​
∫f(x)dx=F(x)🚫
​

We can also write

​
∫dxdy​dx=y🚫
​

Notice the ​dx​ under the integral. This tells us which variable we are integrating with respect to - in this case we are reversing ​dxd​.

The Integration Constant
SL 5.5

Since the derivative of a constant is always zero, then if if ​F′(x)=f(x), then ​(F(x)+C)′=f(x).


This means that when we integrate, we can add any constant to our result, since differentiating makes this constant irrelevant:

​
∫f(x)dx=F(x)+C🚫
​
Anti-Derivative of xⁿ, n∈ℤ
SL 5.5
​
∫xndx=n+1xn+1​+C,n∈Z,n=−1📖
​
Integrals of sums and scalar products
SL 5.5

In the same way that constant multiples can pass through the derivative, they can pass through the integral:

​
∫af(x)dx=a∫f(x)dx🚫
​

And in the same way that the derivative of a sum is the sum of the derivatives:

​
∫f(x)+g(x)dx=∫f(x)dx+∫g(x)dx🚫
​
Boundary Conditions
SL 5.5

If we know the value of ​y​ or ​f(x)​ for a given ​x, we can determine ​C​ by plugging in ​x​ and ​y.

Definite Integrals
SL 5.5

A definite integral is evaluated between a lower and upper bound.

​
∫ab​f(x)dx is the integral of f(x)dx from x=a to x=b
​

We can solve a definite integral with

​
∫ab​f(x)dx=[F(x)]ab​=F(b)−F(a)🚫
​

where ​F(x)=∫f(x)dx.

Calculating Definite Integral with GDC
SL 5.5

Graphing calculators can be used to evaluate definite integrals.


For example, on a TI-84, math > 9:fnInt(, which prompts you with ​∫□□​(□)d□. Make sure the variable of your function matches the variable that you take the integral with respect to.

Definite Integral Rules
SL 5.5

Integrals of the same function with adjacent domains can be merged:

​
∫ab​f(x)dx+∫bc​f(x)dx=∫ac​f(x)dx🚫
​

Similarly, the domain of an integral can be split:

​
∫ab​f(x)dx=∫am​f(x)dx+∫mb​f(x)dx🚫
​

for any ​a<m<b.

Area between curve and x-axis
SL 5.11

In general, the area enclosed between a curve and the ​x​-axis is given by

​
A=∫ab​∣f(x)∣dx📖
​

since any region below the ​x​-axis has ​f(x)<0, but area must always be positive.

This can be done with technology, or by splitting the integral into parts - where ​f​ is positive and where ​f​ is negative:

​
A=∫am​f(x)dx+∫mb​−f(x)dx🚫
​
Area between curves
SL 5.11

The area enclosed between two curves is given by

​
A=∫ab​∣f(x)−g(x)∣dx
​

This can be done with technology, or by splitting the integral into multiple regions, each having either ​f(x)>g(x)​ or ​g(x)>f(x).

Area between curve and y-axis
AHL 5.17

We find the area between a curve and the ​y​-axis by taking an integral with respect to ​y. Integrals with respect to ​y​ have ​y​-value upper and lower bounds and functions in terms of ​y. Therefore,

​
∫ab​∣f(y)∣dy,
​

where ​a​ is the minimum ​y​-value and ​b​ is the maximum value, returns the area between the ​y​-axis and a curve ​f(y):

Nice work completing Definite Integrals, Areas, and Basic Anti-Derivatives, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!
/
Integration
/
Definite Integrals, Areas, and Basic Anti-Derivatives
Anti-Derivative Rules
Definite Integrals, Areas, and Basic Anti-Derivatives
Integration

Definite Integrals, Areas, and Basic Anti-Derivatives

0 of 0 exercises completed

Evaluating definite integrals ​∫ab​f(x)dx=F(b)−F(a), using anti-derivatives ​∫f(x)dx=F(x)+C​ and the power rule ​∫xndx=n+1xn+1​+C​ for ​n=−1, with linearity, splitting or combining intervals, boundary conditions, and finding areas under a curve, between a curve and the ​x​-axis, or between two curves using ​∣f(x)∣​ and ​∣f(x)−g(x)∣.

Want a deeper conceptual understanding? Try our interactive lesson!

Area under a curve
SL 5.5

The area between a curve ​f(x)>0​ and the ​x​-axis is given by

​
A=∫ab​f(x)dx📖
​
Integration as reverse differentiation
SL 5.5

Integration, or anti-differentiation, is essentially the opposite of differentiation. We use the integral symbol​∫​ and write:

​
∫f(x)dx=a function with a derivative off(x)
​

By convention we denote this function ​F:

​
∫f(x)dx=F(x)🚫
​

We can also write

​
∫dxdy​dx=y🚫
​

Notice the ​dx​ under the integral. This tells us which variable we are integrating with respect to - in this case we are reversing ​dxd​.

The Integration Constant
SL 5.5

Since the derivative of a constant is always zero, then if if ​F′(x)=f(x), then ​(F(x)+C)′=f(x).


This means that when we integrate, we can add any constant to our result, since differentiating makes this constant irrelevant:

​
∫f(x)dx=F(x)+C🚫
​
Anti-Derivative of xⁿ, n∈ℤ
SL 5.5
​
∫xndx=n+1xn+1​+C,n∈Z,n=−1📖
​
Integrals of sums and scalar products
SL 5.5

In the same way that constant multiples can pass through the derivative, they can pass through the integral:

​
∫af(x)dx=a∫f(x)dx🚫
​

And in the same way that the derivative of a sum is the sum of the derivatives:

​
∫f(x)+g(x)dx=∫f(x)dx+∫g(x)dx🚫
​
Boundary Conditions
SL 5.5

If we know the value of ​y​ or ​f(x)​ for a given ​x, we can determine ​C​ by plugging in ​x​ and ​y.

Definite Integrals
SL 5.5

A definite integral is evaluated between a lower and upper bound.

​
∫ab​f(x)dx is the integral of f(x)dx from x=a to x=b
​

We can solve a definite integral with

​
∫ab​f(x)dx=[F(x)]ab​=F(b)−F(a)🚫
​

where ​F(x)=∫f(x)dx.

Calculating Definite Integral with GDC
SL 5.5

Graphing calculators can be used to evaluate definite integrals.


For example, on a TI-84, math > 9:fnInt(, which prompts you with ​∫□□​(□)d□. Make sure the variable of your function matches the variable that you take the integral with respect to.

Definite Integral Rules
SL 5.5

Integrals of the same function with adjacent domains can be merged:

​
∫ab​f(x)dx+∫bc​f(x)dx=∫ac​f(x)dx🚫
​

Similarly, the domain of an integral can be split:

​
∫ab​f(x)dx=∫am​f(x)dx+∫mb​f(x)dx🚫
​

for any ​a<m<b.

Area between curve and x-axis
SL 5.11

In general, the area enclosed between a curve and the ​x​-axis is given by

​
A=∫ab​∣f(x)∣dx📖
​

since any region below the ​x​-axis has ​f(x)<0, but area must always be positive.

This can be done with technology, or by splitting the integral into parts - where ​f​ is positive and where ​f​ is negative:

​
A=∫am​f(x)dx+∫mb​−f(x)dx🚫
​
Area between curves
SL 5.11

The area enclosed between two curves is given by

​
A=∫ab​∣f(x)−g(x)∣dx
​

This can be done with technology, or by splitting the integral into multiple regions, each having either ​f(x)>g(x)​ or ​g(x)>f(x).

Area between curve and y-axis
AHL 5.17

We find the area between a curve and the ​y​-axis by taking an integral with respect to ​y. Integrals with respect to ​y​ have ​y​-value upper and lower bounds and functions in terms of ​y. Therefore,

​
∫ab​∣f(y)∣dy,
​

where ​a​ is the minimum ​y​-value and ​b​ is the maximum value, returns the area between the ​y​-axis and a curve ​f(y):

Nice work completing Definite Integrals, Areas, and Basic Anti-Derivatives, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!

Generating starter questions...

1 free

Generating starter questions...

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