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    IB Math AASL
    /
    Quadratics
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    Video

    Video Reviews

    Watch comprehensive video reviews for most units, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Quadratics

    Video Reviews

    Watch comprehensive video reviews for Quadratics, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Quadratics, factors & rootsParabolasProblem solving SL+HLHL only

    The video will automatically pause when it reaches a problem.

    Vertex form & coordinates

    SL AA 2.6

    By completing the square, a quadratic in the form ax2+bx+c can be written in the form

    a(x−h)2+k

    for some h,k∈R.


    Notice that the minimum / maximum (depending on a) of this expression occurs when (x−h)2=0, ie x=h. The resulting y-coordinate is then simply k. Thus the coordinates of the vertex are (h,k). We call this form the vertex height form as it illustrates the connection between the quadratic and its vertex.


    Another way to find the coordinates of the vertex is to remember that it lies on the axis of symmetry, so its x-coordinate is −2ab​. By plugging this value into ax2+bx+c, we can find the y-coordinate


    Example

    Find an equation for the parabola with vertex (3,4) passing through the point (0,−14).


    In vertex height form, the parabola has equation

    a(x−3)2+4

    And since (0,−14) lies on the parabola:

    a(0−3)2+4=−14⇒a=−2


    So the equation is −2(x−3)2+4.

    Vertex form & coordinates

    SL AA 2.6

    By completing the square, a quadratic in the form ax2+bx+c can be written in the form

    a(x−h)2+k

    for some h,k∈R.


    Notice that the minimum / maximum (depending on a) of this expression occurs when (x−h)2=0, ie x=h. The resulting y-coordinate is then simply k. Thus the coordinates of the vertex are (h,k). We call this form the vertex height form as it illustrates the connection between the quadratic and its vertex.


    Another way to find the coordinates of the vertex is to remember that it lies on the axis of symmetry, so its x-coordinate is −2ab​. By plugging this value into ax2+bx+c, we can find the y-coordinate


    Example

    Find an equation for the parabola with vertex (3,4) passing through the point (0,−14).


    In vertex height form, the parabola has equation

    a(x−3)2+4

    And since (0,−14) lies on the parabola:

    a(0−3)2+4=−14⇒a=−2


    So the equation is −2(x−3)2+4.

    Quadratics, factors & rootsParabolasProblem solving SL+HLHL only