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    IB Math AASL
    /
    Distributions & Random Variables
    /

    Video

    Video Reviews

    Watch comprehensive video reviews for most units, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Distributions & Random Variables

    Video Reviews

    Watch comprehensive video reviews for Distributions & Random Variables, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    HL

    The video will automatically pause when it reaches a problem.

    Binomial CDF with Calculator

    SL 4.8

    The binomial cumulative density function tells us the probability of obtaining k or fewer successes in n trials, each with a likelihood of success of p.


    The formula, which you do not need to know or use, is the sum of the binomial pdf formula:

    P(X≤k)=i=0∑k​(ni​)pi(1−p)n−i🚫


    In practice, we use the binomcdf function on our calculators to determine these probabilities.


    Example

    A student is taking a 20 question multiple choice exam where each question is worth 1 point. The student needs to score 11 points for a 5, and 15 points for a 6.


    Given that the probability the student answers each question correctly is 0.6, find the probability that he scored a 5.


    Let X∼B(20,0.6) be the student's score. The student scores a 5 if 11≤X<15 ie 11≤X≤14. We can express this probability as the difference of two probabilities:

    P(11≤X≤14)=P(X≤14)−P(X≤10)


    Using a calculator, we find

    • P(X≤14)=binomcdf(20, 0.6, 14)=0.874401

    • P(X≤10)=binomcdf(20, 0.6, 10)=0.244663

    Subtracting we find P(11≤X≤14)=0.630.


    Note that you get the same result from doing binompdf(20, 0.6, 11)

    +binompdf(20, 0.6,12)

    +binompdf(20, 0.6, 13)

    +binompdf(20, 0.6, 14)

    Binomial CDF with Calculator

    SL 4.8

    The binomial cumulative density function tells us the probability of obtaining k or fewer successes in n trials, each with a likelihood of success of p.


    The formula, which you do not need to know or use, is the sum of the binomial pdf formula:

    P(X≤k)=i=0∑k​(ni​)pi(1−p)n−i🚫


    In practice, we use the binomcdf function on our calculators to determine these probabilities.


    Example

    A student is taking a 20 question multiple choice exam where each question is worth 1 point. The student needs to score 11 points for a 5, and 15 points for a 6.


    Given that the probability the student answers each question correctly is 0.6, find the probability that he scored a 5.


    Let X∼B(20,0.6) be the student's score. The student scores a 5 if 11≤X<15 ie 11≤X≤14. We can express this probability as the difference of two probabilities:

    P(11≤X≤14)=P(X≤14)−P(X≤10)


    Using a calculator, we find

    • P(X≤14)=binomcdf(20, 0.6, 14)=0.874401

    • P(X≤10)=binomcdf(20, 0.6, 10)=0.244663

    Subtracting we find P(11≤X≤14)=0.630.


    Note that you get the same result from doing binompdf(20, 0.6, 11)

    +binompdf(20, 0.6,12)

    +binompdf(20, 0.6, 13)

    +binompdf(20, 0.6, 14)

    HL