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    IB Math AASL
    /
    Cartesian plane & lines
    /

    Skills

    Skill Checklist

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    📖 = included in formula booklet • 🚫 = not in formula booklet

    Track your progress:

    Don't know

    Working on it

    Confident

    📖 = included in formula booklet • 🚫 = not in formula booklet

    Cartesian plane & lines

    Skill Checklist

    Track your progress across all skills in your objective. Mark your confidence level and identify areas to focus on.

    12 Skills Available

    Track your progress:

    Don't know

    Working on it

    Confident

    📖 = included in formula booklet • 🚫 = not in formula booklet

    Track your progress:

    Don't know

    Working on it

    Confident

    📖 = included in formula booklet • 🚫 = not in formula booklet

    Distance, Midpoint, & Gradient

    3 skills
    Distance between 2 points
    SL 2.prior

    The distance between two points (x1​,y1​) and (x2​,y2​) is given by

    d=√(x1​−x2​)2+(y1​−y2​)2​📖

    Powered by Desmos

    Watch video explanation →
    Midpoint of 2 points
    SL 2.prior

    The coordinates of the midpoint of two points is

    (2x1​+x2​​,2y1​+y2​​)📖


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    Finding gradient using 2 points
    SL Core 2.1

    The gradient of the line is a measure of its steepness. It is calculated by measuring the rise (change in y) in the line over a certain run (change in x).


    The gradient of the line passing through the points (x1​,y1​) and (x2​,y2​) is

    m=x2​−x1​y2​−y1​​📖


    Powered by Desmos

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    Equations of a Line

    5 skills
    Gradient-intercept form
    SL Core 2.1

    A straight line is defined by its gradient and its y-intercept. The gradient-intercept equation of a line is thus:

    y=mx+c📖
    Watch video explanation →
    Point-gradient form
    SL Core 2.1

    If we know a point (x1​,y1​) on a line and the gradient m of the line, we can use the point-gradient form of the line:

    y−y1​=m(x−x1​)📖
    Watch video explanation →
    Standard form of a line
    SL Core 2.1

    The equation of a straight line can also be given in the form

    ax+by+d=0📖


    This reduces to

    y=−ba​x−bd​


    In examinations, you may be asked to write the equation of a line in standard form.

    Watch video explanation →
    Horizontal lines
    SL Core 2.1

    A horizontal line has gradient m=0. It is therefore in the form

    y=c

    for some constant c.

    Watch video explanation →
    Vertical lines
    SL Core 2.1

    A vertical line does not have a well defined gradient, since there is no "run" - the x-values never change.


    We cannot write the equation of a vertical line in the form y=⋯. Instead we write

    x=k

    for some constant k.

    Watch video explanation →

    Line Intersections & Systems of Equations

    4 skills
    Parallel lines
    SL Core 2.1

    Two lines are parallel when they have the same gradient m and they do not intersect:

    m1​x+c1​∥m2​x+c2​⇔m1​=m2​ and c1​=c2​

    In this case, the system of equations formed by the two lines has no solutions.


    If the lines have the same gradient and they intersect, then they must be the same line.

    Watch video explanation →
    Perpendicular Lines
    SL Core 2.1

    Two lines are perpendicular if they form a right angle with respect to each other. In this case, the rise of one line becomes the run of the other, with a sign change:

    m1​×m2​=−1

    Powered by Desmos

    Watch video explanation →
    Intersections of straight lines
    SL Core 2.1

    Suppose we have the straight lines y=3x−2 and y=2−3x. Where do the lines intersect?


    Lines intersect when they have a point in common. That is, for some x:

    3x−2=2−3x

    Rearranging gives

    6x=4⇒x=32​


    If two lines do not intersect, then they must be parallel, since the definition of parallel is two straight lines that never meet.


    If two lines are the same (possibly in different forms), then their intersection will all real numbers.

    Watch video explanation →
    Systems of equations with 2 unknowns
    SL Core 2.1

    Suppose we have straight lines with equation 3y+2x−2=0 and 2y−3x+1=0. Where do the lines intersect?


    We have the system of equations

    {3y+2x−2=03y−3x+1=0​


    There are two ways of solving this.

    By substitution

    Rearranging

    3y+2x−2=0⇒y=−32​x+32​


    Substituting this into 3y−3x+1=0:

    (−2x+2)−3x+1=0
    −5x=−3

    So x=53​, which implies y=−32​⋅53​+32​=154​. So the intersection is (53​,154​).


    By elimination

    We can eliminate y from the equations by subtracting the second from the first:

    (3y+2x−2)−(2y−3x+1)2x−2+3x−15x​=0=0=3​

    So x=53​⇒y=154​ and the intersection is again (53​,154​).


    We can use either of these methods to systems of equations with 2 equations and 2 unknowns.

    Watch video explanation →