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    IB Math AASL
    /
    2D & 3D Geometry
    /

    Video

    Video Reviews

    Watch comprehensive video reviews for most units, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    2D & 3D Geometry

    Video Reviews

    Watch comprehensive video reviews for 2D & 3D Geometry, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Right TrianglesNon right trianglesCircles, arc, radians3D solids

    The video will automatically pause when it reaches a problem.

    Ambiguous Case of the Sine rule

    SL 3.5

    The ambiguous case of the sine rule is a consequence of the symmetry of the sin function:

    sin(180°−A)=sin(A)

    Therefore, if a given triangle has a specific sin(A) and it is not specified whether A is acute / obtuse, then there are two possible lengths for the side opposite A:

    Powered by Desmos

    When we type sin−1(x) into the calculator, it will always return an acute angle. To find the corresponding obtuse angle, we take

    180°−sin−1(x)

    Example

    In triangle ABC, the angle A=30° and the sides [BC]=10 and [AC]=12 are given. Find

    • the angle B,

    • the length [AB].

    The angle B is opposite [AC], and A is opposite [BC], so:

    sin(30°)10​=sinB12​⇒sinB=0.6

    This is where the symmetry of sin comes into play: B=sin−1(0.6)=36.9° or B=180°−36.9°=143°


    The resulting length [AB] can be found by finding the angle C=180°−30°−(36.9° or 143°)=113° or 6.87°.


    Thus sinC=0.920 or 0.120. Then

    sinC[AB]​=sinA[BC]​⇒[AB]=20sinC=18.4 or 2.39

    Ambiguous Case of the Sine rule

    SL 3.5

    The ambiguous case of the sine rule is a consequence of the symmetry of the sin function:

    sin(180°−A)=sin(A)

    Therefore, if a given triangle has a specific sin(A) and it is not specified whether A is acute / obtuse, then there are two possible lengths for the side opposite A:

    Powered by Desmos

    When we type sin−1(x) into the calculator, it will always return an acute angle. To find the corresponding obtuse angle, we take

    180°−sin−1(x)

    Example

    In triangle ABC, the angle A=30° and the sides [BC]=10 and [AC]=12 are given. Find

    • the angle B,

    • the length [AB].

    The angle B is opposite [AC], and A is opposite [BC], so:

    sin(30°)10​=sinB12​⇒sinB=0.6

    This is where the symmetry of sin comes into play: B=sin−1(0.6)=36.9° or B=180°−36.9°=143°


    The resulting length [AB] can be found by finding the angle C=180°−30°−(36.9° or 143°)=113° or 6.87°.


    Thus sinC=0.920 or 0.120. Then

    sinC[AB]​=sinA[BC]​⇒[AB]=20sinC=18.4 or 2.39
    Right TrianglesNon right trianglesCircles, arc, radians3D solids