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Perplex
Dashboard
Topics
Exponents & LogarithmsApproximations & ErrorSequences & SeriesCounting & BinomialsProof and Reasoning
Cartesian plane & linesQuadraticsFunction TheoryTransformations & asymptotes
2D & 3D GeometryTrig equations & identities
ProbabilityDescriptive StatisticsBivariate StatisticsDistributions & Random Variables
DifferentiationIntegration
Review VideosFormula BookletMy Progress
BlogLanding Page
Sign UpLogin
Perplex
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Quadratics
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Foundations of Quadratics
Applications of Quadratics
Foundations of Quadratics
Quadratics

Foundations of Quadratics

0 of 0 exercises completed

Vertex, standard, and factored form, axis of symmetry, concavity, quadratic formula

Want a deeper conceptual understanding? Try our interactive lesson!

Vertex and Axis of Symmetry
SL AA 2.6

The graph of a quadratic function has the general shape of a parabola.


It is symmetrical about the axis of symmetry and has a maxima or minima at the vertex, which lies on the axis of symmetry.

General form of a quadratic
SL AA 2.6

A quadratic in ​x​ is an expression of the form

​
ax2+bx+c
​

where ​a=0.

Concavity of a parabola is the sign of a
SL AA 2.6

The concavity of a parabola describes whether it "opens" up or down.

The parabola corresponding to ​ax2+bx+c​ is:

  • Concave up if ​a>0​

  • Concave down if ​a<0.

Factored form of quadratic
SL AA 2.6

Most quadratics can be factored as a product of linear terms:

​
a(x−α)⋅(x−β)
​

We call the generalized form above factored form. Notice that ​α​ and ​β​ are the roots of the quadratic, since when ​x=α​ or ​x=β​ the expression will evaluate to zero.

Factoring by Inspection
SL AA 2.6

We can factor quadratics in the form ​ax2+bx+c​ by splitting ​b​ into a sum ​α+β​ such that that ​αβ​ multiplies to ​ac.


After rewriting the expression as ​ax2+αx+βx+c, factor the first pair and the second pair separately. The common factor will emerge, and you can pull it out. The result is the fully-factored expression.


For example, in the quadratic ​3x2+8x−3, we want to split ​8​ into ​α+β​ such that ​αβ=−9. We can do this by choosing ​α=9​ and ​β=−1:

​
3x2+αx+βx−3=3x(x+3)−1(x+3)​=3x2+9x−x−3=(3x−1)⋅(x+3)​
​
Quadratic x-intercepts
SL AA 2.6

The roots of a quadratic correspond to the ​x​-intercepts of its graph. When ​x=a​ or ​x=β, the entire expression equals zero, which is reflected on the graph.


The equation of the parabola below is ​−(x−α)(x−β): 




Notice that the vertex still remains in the same place as we scale the parabola by ​a, but the squares are "stretched" depending on the value of ​a.


There are two things to notice:

  • The squares are being stretched into rectangles, but the number of shapes in each column is not changing, it's still ​(x−h)2. The height of each column is thus ​a(x−h)2.

  • The vertex does not move - it's height above the ​x​-axis is still ​k.

All of this comes together to create our finished form:

Vertex Form & Coordinates
SL AA 2.6

A quadratic in the form ​ax2+bx+c​ can be written in the form

​
a(x−h)2+k
​

for some ​h,k∈R.

Equation of the axis of symmetry
SL AA 2.6

For the quadratic ​ax2+bx+c, the parabola has an axis of symmetry at

​
x=−2ab​📖
​


The axis of symmetry is the vertical line dividing the parabola perfectly in ​2. The ​x​-coordinate of the vertex, ​h, is equal to the ​x​ value where the axis of symmetry is located.

Completing the square
SL AA 2.6

To convert from the form ​ax2+bx+c​ to ​a(x−h)2+k:​

  1. The values for ​a​ will match up directly.

  2. Use the axis of symmetry ​x=−2ab​​ to find ​h=−2ab​.

  3. Plug ​h​ into ​ax2+bx+c​ to find ​k.

Example

Suppose we want to convert the parabola ​3x2+12x−18​ into vertex form.


First, identify the coefficients. We can see that ​a=3,  ​b=12, and ​c=−18. The axis of symmetry is located at

​
x=−2ab​=−2(3)12​=−2.
​

In vertex form, the axis of symmetry is located at the ​x​-coordinate of the vertex ​(h,k). So ​h=−2.


Since ​k​ is the ​y​-coordinate of the vertex, we can plug ​x=−2​ into ​3x2+12x−18​ to find it:

​
k=3(−2)2+12(−2)−18=−30
​

So in vertex form, the quadratic is

​
3(x+2)2−30
​
Quadratic formula
SL AA 2.6

For any quadratic ​ax2+bx+c, the roots of the quadratic can be found using the quadratic formula:

​
x=2a−b±√b2−4ac​​📖
​
Solving Quadratics with a Calculator
SL Core 2.4

When the values of ​a,b​ or ​c​ are large enough that using the quadratic formula becomes difficult, a calculator can be used to find the roots.


Your calculator should have an app for solving quadratics.

Nice work completing Foundations of Quadratics, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!
/
Quadratics
/
Foundations of Quadratics
Applications of Quadratics
Foundations of Quadratics
Quadratics

Foundations of Quadratics

0 of 0 exercises completed

Vertex, standard, and factored form, axis of symmetry, concavity, quadratic formula

Want a deeper conceptual understanding? Try our interactive lesson!

Vertex and Axis of Symmetry
SL AA 2.6

The graph of a quadratic function has the general shape of a parabola.


It is symmetrical about the axis of symmetry and has a maxima or minima at the vertex, which lies on the axis of symmetry.

General form of a quadratic
SL AA 2.6

A quadratic in ​x​ is an expression of the form

​
ax2+bx+c
​

where ​a=0.

Concavity of a parabola is the sign of a
SL AA 2.6

The concavity of a parabola describes whether it "opens" up or down.

The parabola corresponding to ​ax2+bx+c​ is:

  • Concave up if ​a>0​

  • Concave down if ​a<0.

Factored form of quadratic
SL AA 2.6

Most quadratics can be factored as a product of linear terms:

​
a(x−α)⋅(x−β)
​

We call the generalized form above factored form. Notice that ​α​ and ​β​ are the roots of the quadratic, since when ​x=α​ or ​x=β​ the expression will evaluate to zero.

Factoring by Inspection
SL AA 2.6

We can factor quadratics in the form ​ax2+bx+c​ by splitting ​b​ into a sum ​α+β​ such that that ​αβ​ multiplies to ​ac.


After rewriting the expression as ​ax2+αx+βx+c, factor the first pair and the second pair separately. The common factor will emerge, and you can pull it out. The result is the fully-factored expression.


For example, in the quadratic ​3x2+8x−3, we want to split ​8​ into ​α+β​ such that ​αβ=−9. We can do this by choosing ​α=9​ and ​β=−1:

​
3x2+αx+βx−3=3x(x+3)−1(x+3)​=3x2+9x−x−3=(3x−1)⋅(x+3)​
​
Quadratic x-intercepts
SL AA 2.6

The roots of a quadratic correspond to the ​x​-intercepts of its graph. When ​x=a​ or ​x=β, the entire expression equals zero, which is reflected on the graph.


The equation of the parabola below is ​−(x−α)(x−β): 




Notice that the vertex still remains in the same place as we scale the parabola by ​a, but the squares are "stretched" depending on the value of ​a.


There are two things to notice:

  • The squares are being stretched into rectangles, but the number of shapes in each column is not changing, it's still ​(x−h)2. The height of each column is thus ​a(x−h)2.

  • The vertex does not move - it's height above the ​x​-axis is still ​k.

All of this comes together to create our finished form:

Vertex Form & Coordinates
SL AA 2.6

A quadratic in the form ​ax2+bx+c​ can be written in the form

​
a(x−h)2+k
​

for some ​h,k∈R.

Equation of the axis of symmetry
SL AA 2.6

For the quadratic ​ax2+bx+c, the parabola has an axis of symmetry at

​
x=−2ab​📖
​


The axis of symmetry is the vertical line dividing the parabola perfectly in ​2. The ​x​-coordinate of the vertex, ​h, is equal to the ​x​ value where the axis of symmetry is located.

Completing the square
SL AA 2.6

To convert from the form ​ax2+bx+c​ to ​a(x−h)2+k:​

  1. The values for ​a​ will match up directly.

  2. Use the axis of symmetry ​x=−2ab​​ to find ​h=−2ab​.

  3. Plug ​h​ into ​ax2+bx+c​ to find ​k.

Example

Suppose we want to convert the parabola ​3x2+12x−18​ into vertex form.


First, identify the coefficients. We can see that ​a=3,  ​b=12, and ​c=−18. The axis of symmetry is located at

​
x=−2ab​=−2(3)12​=−2.
​

In vertex form, the axis of symmetry is located at the ​x​-coordinate of the vertex ​(h,k). So ​h=−2.


Since ​k​ is the ​y​-coordinate of the vertex, we can plug ​x=−2​ into ​3x2+12x−18​ to find it:

​
k=3(−2)2+12(−2)−18=−30
​

So in vertex form, the quadratic is

​
3(x+2)2−30
​
Quadratic formula
SL AA 2.6

For any quadratic ​ax2+bx+c, the roots of the quadratic can be found using the quadratic formula:

​
x=2a−b±√b2−4ac​​📖
​
Solving Quadratics with a Calculator
SL Core 2.4

When the values of ​a,b​ or ​c​ are large enough that using the quadratic formula becomes difficult, a calculator can be used to find the roots.


Your calculator should have an app for solving quadratics.

Nice work completing Foundations of Quadratics, here's a quick recap of what we covered:

Skills covered

Mixed Practice

Exercises checked off

I'm Plex, here to help you understand this concept!

Generating starter questions...

Generating starter questions...