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    IB Math AAHL
    /
    Proof and Reasoning
    /

    Video

    Video Reviews

    Watch comprehensive video reviews for most units, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Proof and Reasoning

    Video Reviews

    Watch comprehensive video reviews for Proof and Reasoning, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Direct proof (SL + HL)HL Terms & DefinitionsContradiction (HL)Proof by induction

    The video will automatically pause when it reaches a problem.

    Rational Numbers

    AHL AA 1.15

    A rational number is one that can be written in the form

    p=ba​,a,b∈Z


    Note that any fraction can be reduced to the point where the numerator and denominator share no common factors:

    155​=31​


    So if a number is rational, then it can be written as a fraction of integers with no common factors. This property is essential for a classic (and common IB) proof:


    Example

    Prove that √2 is irrational.


    Suppose that √2 is rational, that is

    √2=ba​

    for a,b∈Z where a and b have no common factors. Squaring both sides:

    2=b2a2​⇒2b2=a2

    which means that 2∣a2. But since 2 is prime, that means 2∣a, ie that a=2k for some k∈Z:

    2b2=a22b2⇒b2​=(2k)2=4k2=2k2​

    which means that 2∣b2. But (again) since 2 is prime, 2∣b.


    Therefore 2 divides both a and b. But this contradicts the assumption that a and b have no common factors.


    Hence, by contradiction, √2 is irrational.


    Notice that this proof does not work, for example, on √4 since 4 is not prime!

    Rational Numbers

    AHL AA 1.15

    A rational number is one that can be written in the form

    p=ba​,a,b∈Z


    Note that any fraction can be reduced to the point where the numerator and denominator share no common factors:

    155​=31​


    So if a number is rational, then it can be written as a fraction of integers with no common factors. This property is essential for a classic (and common IB) proof:


    Example

    Prove that √2 is irrational.


    Suppose that √2 is rational, that is

    √2=ba​

    for a,b∈Z where a and b have no common factors. Squaring both sides:

    2=b2a2​⇒2b2=a2

    which means that 2∣a2. But since 2 is prime, that means 2∣a, ie that a=2k for some k∈Z:

    2b2=a22b2⇒b2​=(2k)2=4k2=2k2​

    which means that 2∣b2. But (again) since 2 is prime, 2∣b.


    Therefore 2 divides both a and b. But this contradicts the assumption that a and b have no common factors.


    Hence, by contradiction, √2 is irrational.


    Notice that this proof does not work, for example, on √4 since 4 is not prime!

    Direct proof (SL + HL)HL Terms & DefinitionsContradiction (HL)Proof by induction