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    IB Math AAHL
    /
    Proof and Reasoning
    /

    Video

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    Watch comprehensive video reviews for most units, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

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    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Proof and Reasoning

    Video Reviews

    Watch comprehensive video reviews for Proof and Reasoning, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Not your average video:

    Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.

    Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.

    Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.

    Direct proof (SL + HL)HL Terms & DefinitionsContradiction (HL)Proof by induction

    The video will automatically pause when it reaches a problem.

    Prime Numbers

    AHL AA 1.15

    A prime number is a natural number greater than 1 that has exactly two distinct positive divisors: 1 and itself. For example, the set of prime numbers begins as

    {2,3,5,7,11…}

    Notice that 1 is not included in this list because it has only one positive divisor (namely, itself), and thus does not meet the definition.


    Example

    Prove by contradiction that there are infinitely many primes.


    Assume for contradiction that there are only finitely many primes, say

    p1​,p2​,…,pn​.

    Now, define

    Q=p1​⋅p2​⋯pn​+1.

    If Q is prime, then Q is a prime number that is not among the listed primes p1​,p2​,…,pn​ (since Q>pi​ for each i), which contradicts the assumption that all primes have been listed.


    If Q is not prime, then it must have a prime divisor, say p, in our finite list. Thus p divides the product p1​⋅p2​⋯pn​:

    p∣(p1​⋅p2​⋯pn​).

    So

    (p1​⋅p2​⋯pn​)=pk

    and

    Q=pn

    for some k,n∈Z.


    Thus

    Q−(p1​⋅p2​⋯pn​)=pk−pn=p(k−n)

    Thus, p must also divide the difference

    Q−(p1​⋅p2​⋯pn​)=1.

    But no prime divides 1. This is a contradiction.

    Therefore, there are infinitely many prime numbers. Q.E.D.

    Prime Numbers

    AHL AA 1.15

    A prime number is a natural number greater than 1 that has exactly two distinct positive divisors: 1 and itself. For example, the set of prime numbers begins as

    {2,3,5,7,11…}

    Notice that 1 is not included in this list because it has only one positive divisor (namely, itself), and thus does not meet the definition.


    Example

    Prove by contradiction that there are infinitely many primes.


    Assume for contradiction that there are only finitely many primes, say

    p1​,p2​,…,pn​.

    Now, define

    Q=p1​⋅p2​⋯pn​+1.

    If Q is prime, then Q is a prime number that is not among the listed primes p1​,p2​,…,pn​ (since Q>pi​ for each i), which contradicts the assumption that all primes have been listed.


    If Q is not prime, then it must have a prime divisor, say p, in our finite list. Thus p divides the product p1​⋅p2​⋯pn​:

    p∣(p1​⋅p2​⋯pn​).

    So

    (p1​⋅p2​⋯pn​)=pk

    and

    Q=pn

    for some k,n∈Z.


    Thus

    Q−(p1​⋅p2​⋯pn​)=pk−pn=p(k−n)

    Thus, p must also divide the difference

    Q−(p1​⋅p2​⋯pn​)=1.

    But no prime divides 1. This is a contradiction.

    Therefore, there are infinitely many prime numbers. Q.E.D.

    Direct proof (SL + HL)HL Terms & DefinitionsContradiction (HL)Proof by induction