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Not your average video:
Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.
Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.
Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.
Counting & Binomials
Watch comprehensive video reviews for Counting & Binomials, designed for final exam preparation. Each video includes integrated problems you can solve alongside detailed solutions.
Not your average video:
Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.
Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.
Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.
Not your average video:
Interactive Problems: Solve problems alongside the video with step-by-step guidance and detailed solutions.
Exam Preparation: Complete unit reviews designed for final exam preparation with all key concepts covered systematically.
Expert Teaching: High-quality instruction from Perplex co-founder James Mullen with clear explanations, worked examples, and exam tips.
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AHL AA 1.10
Permutations are arrangements of items where the order of the items matters.
The number of ways of permuting r items from a set of n items is similar to the n! for ordering n items, but we have to stop the multiplication after r items - when there are (n−r) remaining items.
The number of permutations is thus:
Example
Anna is setting a new 4 digit pin code on her mobile phone. How many possible codes can she make if she does not reuse any digits?
There are n=10 digits (0−9), and the pin length is r=4. The order of the digits does matter, and digits cannot be reused, so the number of possible codes is
(using a calculator)
AHL AA 1.10
Permutations are arrangements of items where the order of the items matters.
The number of ways of permuting r items from a set of n items is similar to the n! for ordering n items, but we have to stop the multiplication after r items - when there are (n−r) remaining items.
The number of permutations is thus:
Example
Anna is setting a new 4 digit pin code on her mobile phone. How many possible codes can she make if she does not reuse any digits?
There are n=10 digits (0−9), and the pin length is r=4. The order of the digits does matter, and digits cannot be reused, so the number of possible codes is
(using a calculator)