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  • erplex
    IB Math AAHL
    /
    Complex Numbers
    /

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    Complex Numbers

    Skill Checklist

    Track your progress across all skills in your objective. Mark your confidence level and identify areas to focus on.

    23 Skills Available

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    Cartesian form

    10 skills
    Imaginary number i
    AHL HL 1.12

    The imaginary number i is the square root of −1:

    i=√−1​⇔i2=−1🚫


    In general, imaginary numbers are of the form bi,b∈R∖{0}. Notice that

    (bi)2=b2i2=−b2<0

    Conclusion: the square of any imaginary number is negative.

    Watch video explanation →
    Complex Numbers a+bi
    AHL HL 1.12

    A complex number

    z=a+bi📖

    is the sum of a real number a and an imaginary number bi.


    We call a the real part of z and b the imaginary part of z:

    Re(z)Im(z)​=a=b​


    For example, z=2−3i is a complex number with a real part Re(z)=2 and imaginary part Im(z)=−3.


    If two complex numbers are equal, then both their real and imaginary parts are equal:

    a+bi=x+yi⇔{a=xb=y​🚫

    The expression x+iy is often referred to as the Cartesian form of z.

    Watch video explanation →
    The sets ℂ, ℝ and ℝ\ℂ
    AHL HL 1.12

    Real numbers are a subset of complex numbers a+bi where b=0. Imaginary numbers are also a subset of complex numbers with a=0.

    Powered by Desmos

    Watch video explanation →
    Product of complex numbers
    AHL HL 1.12

    The product of two complex numbers in Cartesian form is

    (a+bi)×(c+di)  ​=ac+adi+bci+bdi2=ac+i(ad+bd)+bd⋅(−1)=ac−bd+(ad+bd)i​🚫
    Watch video explanation →
    The complex plane
    AHL HL 1.12

    Complex numbers can be visualized in the complex plane, also known as the Argand Diagram.


    To plot a complex number, the real part determines the x-coordinate and the imaginary part determines the y-coordinate. Therefore the complex number a+bi has coordinates (a,b) on the plane.


    It is conventional to use arrows from the origin to the point (a,b) to represent complex numbers.


    Powered by Desmos

    Watch video explanation →
    Complex conjugates
    AHL HL 1.12

    The conjugate of a complex number z is the complex number with the same real component and the opposite imaginary component:

    z=a+bi⇔z∗=a−bi🚫

    Since the real components of z and z∗ are the same, and the imaginary components are opposite, on the complex plane z∗ is the reflection of z in the x-axis.

    Powered by Desmos

    Watch video explanation →
    Properties of the complex conjugate
    AHL HL 1.12

    The following properties hold for complex conjugates:

    (z∗)∗=z🚫


    (z±w)∗=z∗±w∗🚫


    (zw)∗=z∗w∗🚫


    (wz​)∗=w∗z∗​🚫
    Watch video explanation →
    Fractions of complex numbers
    AHL HL 1.12

    Fractions with complex denominator can be made real using a process analogous to rationalizing the denominator. For a fraction with a complex denominator c+di, we multiply both the numerator and the denominator by the conjugate c−di to get the fraction in a more workable form:

    z=c+dia+bi​​=c+dia+bi​⋅c−dic−di​​

    This allows us to split z into its real and imaginary components.

    Watch video explanation →
    Solving complex equations
    AHL HL 1.12

    We can solve complex equations involving z and z∗ by using the fact that a complex number z takes the form a+bi. Recall that for complex numbers z1​ and z2​,

    z1​=z2​⟺{Re(z1​)=Re(z2​)Im(z1​)=Im(z2​)​


    We use this fact to equate the real and imaginary parts of both sides, which creates a solvable a system of two equations in two unknowns from one given equation.

    Watch video explanation →
    Finding complex roots of quadratics
    AHL HL 1.12

    When a quadratic

    ax2+bx+c=0

    has

    Δ=b2−4ac<0,

    it has no real roots since the square root in

    x=2a−b±√b2−4ac​​

    is not a real number. Instead, the square root will give an imaginary number, making the roots complex.

    Watch video explanation →

    Complex Modulus

    4 skills
    Complex Modulus
    AHL HL 1.12

    The complex modulus ∣z∣ is a measure of the size of a complex number:

    ∣z∣=√a2+b2​🚫
    Watch video explanation →
    Modulus on the complex plane
    AHL HL 1.12

    On the complex plane, z=a+bi has coordinates (a,b). Therefore

    ∣z∣=√a2+b2​🚫

    represents the distance of z from the origin:

    Powered by Desmos

    Watch video explanation →
    zz*=|z|²
    AHL HL 1.12

    Notice that

    zz∗=(a+bi)(a−bi)=a2+b2=∣z∣2🚫
    Watch video explanation →
    Properties of complex modulus
    AHL HL 1.12

    The following properties apply for the complex modulus:

    ∣z∗∣=∣z∣🚫
    ∣zw∣=∣z∥w∣🚫
    ∣∣∣​wz​∣∣∣​=∣w∣∣z∣​🚫
    ∣zn∣=∣z∣n🚫
    Watch video explanation →

    Mod-arg & Polar forms

    7 skills
    Complex Argument
    AHL HL 1.12

    The argument of a complex number is the angle that it forms with the real (x) axis on the complex plane:

    Powered by Desmos

    By noticing a right angled triangle, we can say that

    tan(argz)=ab​🚫

    When a>0:

    argz=arctan(ab​)🚫


    Note on convention: By convention, the argument is usually given in radians in the range [−π,π]. It will be made clear by the IB which range is preferred in a given question.

    Watch video explanation →
    Complex argument when a<0
    AHL HL 1.12

    If a<0, then argz is in the second or third quadrant, which are not in the range of arctan. We therefore need to add or subtract π to get the correct argument:

    Powered by Desmos

    When a<0:

    arg(z)=arctan(ab​)±π🚫

    When z is in the second quadrant, we add π; when z is in the third quadrant, we subtract π.


    Note on convention: By convention, the argument is usually given in radians in the range [−π,π]. It will be made clear by the IB which range is preferred in a given question.

    Watch video explanation →
    Complex Argument when a=0 (purely imaginary)
    AHL HL 1.12

    If a=0, then tan(argz)=ab​ is undefined. tanθ is also undefined for θ=2π​,23π​… So when a=0 we have

    arg(bi)=⎩⎪⎪⎪⎨⎪⎪⎪⎧​2π​b>0 −2π​b<0​🚫


    This can be seen on the complex diagram by remembering that bi lies on the yi axis:

    Powered by Desmos


    Note on convention: By convention, the argument is usually given in radians in the range [−π,π]. It will be made clear by the IB which range is preferred in a given question.

    Watch video explanation →
    Polar form of complex numbers
    AHL AA 1.13

    The modulus ∣z∣ and argument argz uniquely define the complex number z. That means we can represent any complex number using its modulus and argument instead of a+bi:

    Powered by Desmos

    It is conventional to call r=∣z∣ and θ=argz. Using trigonometry, we deduce that

    z=r(cosθ+isinθ)📖

    And we use the shorthand cisθ=cosθ+isinθ:

    z=rcisθ📖
    Watch video explanation →
    Euler's form
    AHL AA 1.13

    There is one more way to express complex numbers:

    z=rcisθ=reiθ📖

    For example, we can write z=−1=1⋅cis(π)=eiπ. This leads to the classic result

    eiπ+1=0🚫

    We call this Euler's form (or sometimes exponential form) because of the presence of Euler's number, e.

    Watch video explanation →
    Multiplying in mod-arg form
    AHL AA 1.13

    The main advantage of Euler's form is that it makes multiplying complex numbers much easier:

    r1​eiα⋅r2​eiβ=r1​r2​ei(α+β)🚫

    In words, when we multiply two complex numbers the arguments add and the moduli multiply.


    Similarly for division:

    r2​eiβr1​eiα​=r2​r1​​ei(α−β)🚫

    In words, when we divide one complex number from another, we subtract the arguments and divide the moduli.

    Watch video explanation →
    Complex conjugate in polar form
    AHL AA 1.13

    If z=rcisθ=reiθ, then the conjugate z∗ is

    z∗=rcis(−θ)=re−iθ🚫
    Watch video explanation →

    De Moivre's Theorem

    2 skills
    Powers of complex numbers
    AHL AA 1.14

    Now that we know how to represent complex numbers in the form reiθ, we can understand De Moivre's Theorem, which gives us a shortcut to finding powers of complex numbers:

    z=reiθ⇒zn=(reiθ)n=rneinθ


    And since reiθ=rcisθ:

    [r(cosθ+isinθ)]n=(rcisθ)n=rneinθ=rncis(nθ)📖
    Watch video explanation →
    Roots of complex numbers
    AHL AA 1.14

    De Moivre's Theorem can also be used to find the nth roots of complex numbers:

    n√reiθ=(reiθ)1/n=n√r⋅eiθ/n🚫

    or equivalently

    n√rcisθ=n√rcis(nθ​)🚫


    However, since cisθ=cis(θ+2kπ) for any k∈Z, then we actually have

    n√rcisθ=n√rcis(nθ+2kπ​),k=0,1…n−1🚫

    Note that k stops at n−1 since when k=n we have

    cis(nθ+2nπ​)=cis(θ+2π)=cisθ
    Watch video explanation →